24x^2-86x+72=0

Solution for 24x^2-86x+72=0 equation:

24x^2-86x+72=0

a = 24; b = -86; c = +72;
Δ = b2-4ac
Δ = -862-4·24·72
Δ = 484
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{484}=22$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-86)-22}{2*24}=\frac{64}{48}
=1+1/3
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-86)+22}{2*24}=\frac{108}{48}
=2+1/4
$